Three Dimensional Geometry Question 231
Question: The equation of the line passing through the points ( 3, 2, 4) and (4, 5, 2) is
Options:
A) $ \frac{x+3}{1}=\frac{y+2}{3}=\frac{z+4}{-2} $
B) $ \frac{x-3}{1}=\frac{y-2}{3}=\frac{z-4}{-2} $
C) $ \frac{x+3}{7}=\frac{y+2}{7}=\frac{z+4}{6} $
D) $ \frac{x-3}{7}=\frac{y-2}{7}=\frac{z-4}{6} $
Show Answer
Answer:
Correct Answer: B
Solution:
Required line is $ \frac{x-3}{4-3}=\frac{y-2}{5-2}=\frac{z-4}{2-4} $ i.e., $ \frac{x-3}{1}=\frac{y-2}{3}=\frac{z-4}{-2} $ .
BETA
