Three Dimensional Geometry Question 252
Question: If a plane cuts off intercepts ?6, 3, 4 from the co-ordinate axes, then the length of the perpendicular from the origin to the plane is
Options:
A) $ \frac{1}{\sqrt{61}} $
B) $ \frac{13}{\sqrt{61}} $
C) $ \frac{12}{\sqrt{29}} $
D) $ \frac{5}{\sqrt{41}} $
Show Answer
Answer:
Correct Answer: C
Solution:
Equation is $ \frac{x}{-6}+\frac{y}{3}+\frac{z}{4}=1 $ or $ -2x+4y+3z=12 $
$ \therefore $ Length of perpendicular from origin $ =\frac{12}{\sqrt{4+16+9}}=\frac{12}{\sqrt{29}} $ .
BETA
