Three Dimensional Geometry Question 258
Question: The equation of the plane which bisects the angle between the planes $ 3x-6y+2z+5=0 $ and $ 4x-12y+3z-3=0 $ which contains the origin is
Options:
A) $ 33x-13y+32z+45=0 $
B) $ x-3y+z-5=0 $
C) $ 33x+13y+32z+45=0 $
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
Equation of plane bisecting the angle containing origin is (making constant term of same sign) $ \frac{-3x+6y-2z-5}{\sqrt{3^{2}+6^{2}+2^{2}}}=+[ \frac{4x-12y+3z-3}{\sqrt{4^{2}+12^{2}+3^{2}}} ] $ or $ \frac{-3x+6y-2z-5}{7}=\frac{4x-12y+3z-3}{13} $ or $ 67x-162y+47z+44=0 $ .
BETA
