Three Dimensional Geometry Question 261
Question: The distance between the planes $ x+2y+3z+7=0 $ and $ 2x+4y+6z+7=0 $ is
[MP PET 1991]
Options:
A) $ \frac{\sqrt{7}}{2\sqrt{2}} $
B) $ \frac{7}{2} $
C) $ \frac{\sqrt{7}}{2} $
D) $ \frac{7}{2\sqrt{2}} $
Show Answer
Answer:
Correct Answer: A
Solution:
Required distance = $ \frac{7-\frac{7}{2}}{\sqrt{1+4+9}}=\frac{\sqrt{7}}{2\sqrt{2}} $ .
BETA
