Three Dimensional Geometry Question 264
Question: The equation of the plane which is parallel to the plane $ x-2y+2z=5 $ and whose distance from the point $ (1,,2,,3) $ is 1, is
Options:
A) $ x-2y+2z=3 $
B) $ x-2y+2z+3=0 $
C) $ x-2y+2z=6 $
D) $ x-2y+2z+6=0 $
Show Answer
Answer:
Correct Answer: C
Solution:
Equation of plane parallel to $ x-2y+2z=5 $ is $ x-2y+2z+k=0 $ ?..(i) Now, according to question, $ \frac{1-4+6+k}{\sqrt{9}}=\pm 1 $ or $ k+3=\pm ,3\Rightarrow k=0 $ or ? 6
$ \therefore x-2y+2z-6=0 $ or $ x-2y+2z=6 $ .
BETA
