Three Dimensional Geometry Question 265
Question: The equation of the plane through (1, 2, 3) and parallel to the plane $ 2x+3y-4z=0 $ is
[MP PET 1990]
Options:
A) $ 2x+3y+4z=4 $
B) $ 2x+3y+4z+4=0 $
C) $ 2x-3y+4z+4=0 $
D) $ 2x+3y-4z+4=0 $
Show Answer
Answer:
Correct Answer: D
Solution:
Plane parallel to the plane $ 2x+3y-4z=0 $ is $ 2x+3y-4z+k=0 $ …..(i) Also plane (i) is passing through (1, 2, 3)
$ \therefore $ $ (2),(1)+(3)(2)-(4)(3)+k=0\Rightarrow k=4 $
$ \therefore $ Required plane is $ 2x+3y-4z+4=0 $ .
BETA
