Three Dimensional Geometry Question 273
Question: A point moves so that its distances from the points (3, 4, ?2) and (2, 3, ? 3) remains equal. The locus of the point is
Options:
A) A line
B) A plane whose normal is equally inclined to axes
C) A plane which passes through the origin
D) A sphere
Show Answer
Answer:
Correct Answer: B
Solution:
According to question, $ {{(x-3)}^{2}}+{{(y-4)}^{2}}+{{(z+2)}^{2}}={{(x-2)}^{2}}+{{(y-3)}^{2}}+{{(z+3)}^{2}} $
$ \therefore $ The equation reduces to a plane as 2nd degree terms cancel out. The equation is $ 2x+2y+2z=7, $ hence equally inclined to axes.
BETA
