Three Dimensional Geometry Question 278
Question: The equation of the plane through the point (1, 2, 3 ) and parallel to the plane $ x+2y+5z=0 $ is
[DCE 2002]
Options:
A) $ (x-1)+2(y-2)+5(z-3)=0 $
B) $ x+2y+5z=14 $
C) $ x+2y+5z=6 $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Equation of plane passing through the point (1, 2, 3) is $ A(x-1)+B(y-2)+C(z-3)=0 $ …..(i) Plane (i) is parallel to plane $ x+2y+5z=0 $ \ $ (x-1)+2(y-2)+5(z-3)=0 $ is the required plane.
BETA
