Three Dimensional Geometry Question 28
Question: Let (3, 4, ?1) and (?1, 2, 3) are the end points of a diameter of sphere. Then the radius of the sphere is equal to
[Orissa JEE 2003]
Options:
A) 1
B) 2
C) 3
D) 9
Show Answer
Answer:
Correct Answer: C
Solution:
$ d=\sqrt{{{(-1-3)}^{2}}+{{(2-4)}^{2}}+{{(3+1)}^{2}}} $ = $ \sqrt{16+4+16} $ $ =\sqrt{36}=6 $
So, radius $ r=\frac{d}{2}=\frac{6}{2}=3. $
BETA
