Three Dimensional Geometry Question 281
Question: The equation of a plane which passes through (2, ?3, 1) and is normal to the line joining the points (3, 4, ?1) and (2, ?1, 5) is given by
[AI CBSE 1990; MP PET 1993]
Options:
A) $ x+5y-6z+19=0 $
B) $ x-5y+6z-19=0 $
C) $ x+5y+6z+19=0 $
D) $ x-5y-6z-19=0 $
Show Answer
Answer:
Correct Answer: A
Solution:
Obviously, $ (x-2)+5(y+3)-6(z-1)=0 $
$ \Rightarrow x+5y-6z+19=0 $ .
BETA
