Three Dimensional Geometry Question 286
Question: The distance of the plane $ 6x-3y+2z-14=0 $ from the origin is
[MP PET 2003]
Options:
A) 2
B) 1
C) 14
D) 8
Show Answer
Answer:
Correct Answer: A
Solution:
Distance of plane from origin = $ \frac{d}{\sqrt{a^{2}+b^{2}+c^{2}}} $ $ =\frac{14}{\sqrt{6^{2}+3^{2}+2^{2}}}=\frac{14}{\sqrt{49}}=\frac{14}{7}=2 $ .
BETA
