Three Dimensional Geometry Question 288
Question: The equation of the plane through the three points (1, 1, 1), (1, ?1, 1) and (?7,?3,?5), is
[AISSE 1984]
Options:
A) $ 3x-4z+1=0 $
B) $ 3x-4y+1=0 $
C) $ 3x+4y+1=0 $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Plane passing through (1, 1, 1) is $ a,(x-1)+b,(y-1)+c,(z-1)=0 $ It also passes through (1, ? 1, 1) and (?7, ? 3, ? 5), then $ b=0,a=-\frac{3}{4}c $ Hence the required equation is $ 3x-4z+1=0 $ . Trick : Since the plane $ 3x-4z+1=0 $ passes through given three points.
BETA
