Three Dimensional Geometry Question 325
Question: Distance between parallel planes $ 2x-2y+z+3=0 $ and $ 4x-4y+2z+5=0 $ is
[MP PET 1994, 95]
Options:
A) $ \frac{2}{3} $
B) $ \frac{1}{3} $
C) $ \frac{1}{6} $
D) 2
Show Answer
Answer:
Correct Answer: C
Solution:
The required distance is given by $ | \frac{3}{\sqrt{2^{2}+2^{2}+1^{2}}}-\frac{5}{\sqrt{4^{2}+4^{2}+2^{2}}} |=| 1-\frac{5}{6} |=\frac{1}{6} $ .