Three Dimensional Geometry Question 325

Question: Distance between parallel planes $ 2x-2y+z+3=0 $ and $ 4x-4y+2z+5=0 $ is

[MP PET 1994, 95]

Options:

A) $ \frac{2}{3} $

B) $ \frac{1}{3} $

C) $ \frac{1}{6} $

D) 2

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Answer:

Correct Answer: C

Solution:

The required distance is given by $ | \frac{3}{\sqrt{2^{2}+2^{2}+1^{2}}}-\frac{5}{\sqrt{4^{2}+4^{2}+2^{2}}} |=| 1-\frac{5}{6} |=\frac{1}{6} $ .