Three Dimensional Geometry Question 328
Question: The co-ordinates of the points A and B are (2, 3, 4) and (-2, 5, -4) respectively. If a point P moves so that $ PA^{2}-PB^{2}=k $ where k is a constant, then the locus of P is
Options:
A) $ -8x+4y-16z+16=k $
B) $ -8x-4y-16z-16=k $
C) $ -8x+4y-16z-16=k $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ \because PA^{2}-PB^{2}=k $
$ \therefore ,[{{(x-2)}^{2}}+{{(y-3)}^{2}}+{{(z-4)}^{2}}] $ $ =[{{(x+2)}^{2}}+{{(y-5)}^{2}}+{{(z+4)}^{2}}]=k $ or $ -8x+4y-16z-16=k, $
BETA
