Three Dimensional Geometry Question 339
Question: The distance of the point (2, 3, 4) from the line $ 1-x=\frac{y}{2}=\frac{1}{3}(1+z) $ is
[J & K 2005]
Options:
A) $ \frac{1}{7}\sqrt{35} $
B) $ \frac{4}{7}\sqrt{35} $
C) $ \frac{2}{7}\sqrt{35} $
D) $ \frac{3}{7}\sqrt{35} $
Show Answer
Answer:
Correct Answer: D
Solution:
Required distance = $ \sqrt{\sum {{(x_1-x_2)}^{2}}-{{[\sum l(x_1-x_2)]}^{2}}} $ $ =\frac{3}{7}\sqrt{35} $ .
BETA
