Three Dimensional Geometry Question 358
Question: The line $ \frac{x-3}{2}=\frac{y-4}{3}=\frac{z-5}{4} $ lies in the plane $ 4x+4y-kz-d=0 $ . The values of k and d are
Options:
A) 4, 8
B) -5, -3
C) 5, 3
D) - 4, - 8
Show Answer
Answer:
Correct Answer: C
Solution:
Since the line lies on the given plane, therefore any point on the line will satisfy the plane i.e., the points (3, 4, 5) and (5, 7, 9) will lie on the plane. Hence $ k=5,d=3. $
BETA
