Three Dimensional Geometry Question 362

Question: If the foot of the perpendicular from the origin to a plane is P (a, b, c), the equation of the plane is

Options:

A) $ \frac{x}{a}+\frac{y}{b}+\frac{z}{c}=3 $

B) $ ax+by+cz=3 $

C) $ ax+by+cz=a^{2}+b^{2}+c^{2} $

D) $ ax+by+cz=a+b+c $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Direction ratios of OP are (a, b, c) Therefore, equation of the plane is $ a(x-a)+b(y-b)+c(z-c)=0 $ i.e., $ xa+yb+zc=a^{2}+b^{2}+c^{2} $



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