Three Dimensional Geometry Question 376
Question: Value of $ \lambda $ such that the line $ \frac{x-1}{2}=\frac{y-1}{3}=\frac{z-1}{\lambda } $ Is perpendicular to normal to the plane $ \vec{r}.(2\vec{i}+3\vec{j}+4\vec{k})=0 $ is
Options:
A) $ -\frac{13}{4} $
B) $ -\frac{17}{4} $
C) $ 4 $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Since the line is parallel to the plane vector $ 2\vec{i}+3\vec{j}+\lambda \vec{k} $ is perpendicular to the normal to the plane $ 2\vec{i}+3\vec{j}+4\vec{k} $ $ \Rightarrow 2\times 2+3\times 3+4\lambda =0 $ or $ \lambda =-\frac{13}{4} $
BETA
