Three Dimensional Geometry Question 382
Question: The angle between the line $ \frac{x-2}{a}=\frac{y-2}{b}=\frac{z-2}{c} $ and the plane $ ax+by+cz+6=0 $ is
Options:
A) $ {{\sin }^{-1}}( \frac{1}{\sqrt{a^{2}+b^{2}+c^{2}}} ) $
B) $ 45{}^\circ $
C) $ 60{}^\circ $
D) $ 90{}^\circ $
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Answer:
Correct Answer: D
Solution:
[d] Obviously the line perpendicular to the plane because $ \frac{a}{a}=\frac{b}{b}=\frac{c}{c} $ i.e., their direction ratios are proportional.
BETA
