Three Dimensional Geometry Question 390
Question: The equation of the plane through the intersection of the planes $ x+2y+3z-4=0 $ , $ 4x+3y+2z+1=0 $ and passing through the origin will be
[MP PET 1998]
Options:
A) $ x+y+z=0 $
B) $ 17x+14y+11z=0 $
C) $ 7x+4y+z=0 $
D) $ 17x+14y+z=0 $
Show Answer
Answer:
Correct Answer: B
Solution:
Equation of plane passing through intersecting the planes $ x+2y+3z-4=0 $ and $ 4x+3y+2z+1=0 $ is, $ x+2y+3z-4+\lambda ,(4x+3y+2z+1)=0 $
Since it is passing through origin, so $ \lambda =4. $
Hence the required equation is $ 17x+14y+11z=0. $
BETA
