Three Dimensional Geometry Question 393
Question: If Q is the image of the point P(2, 3, 4) under the reflection in the plane $ x-2y+5z=6 $ , then the equation of the line $ PQ $ is
Options:
A) $ \frac{x-2}{-1}=\frac{y-3}{2}=\frac{z-4}{5} $
B) $ \frac{x-2}{1}=\frac{y-3}{-2}=\frac{z-4}{5} $
C) $ \frac{x-2}{-1}=\frac{y-3}{-2}=\frac{z-4}{5} $
D) $ \frac{x-2}{1}=\frac{y-3}{2}=\frac{z-4}{5} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Let Q be the image of the point $ P(2,3,4) $ in the plane $ x-2y+5z=6, $ then PQ is normal to the plane
$ \therefore $ Direction ratios of PQ are <1,-2, 5> Since PQ passes through P (2, 3, 4) and has direction ratios 1, -2, 5
$ \therefore $ Equation of PQ is $ \frac{(x-2)}{1}=\frac{y-3}{-2}=\frac{z-4}{5} $
BETA
