Three Dimensional Geometry Question 394
Question: Under which one of the following condition will the two planes $ x+y+z=7 $ and $ \alpha x+\beta y+\gamma z=3 $ , be parallel (but not coincident)?
Options:
A) $ \alpha =\beta =\gamma =1only $
B) $ \alpha =\beta =\gamma =\frac{3}{7}only $
C) $ \alpha =\beta =\gamma $
D) None of the above
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Given equation of planes are: $ x+y+z=7 $ and $ \alpha x+\beta y+\gamma z=3 $ For these planes to be parallel, coefficients of x, y and z should be same i.e.
$ \Rightarrow \alpha =\beta =\gamma $
BETA
