Three Dimensional Geometry Question 41

Question: The plane $ ax+by+cz=1 $ meets the co-ordinate axes in A, B and C. The centroid of the triangle is

[CET 1992]

Options:

A) $ (3a,3b,3c) $

B) $ ( \frac{a}{3},\frac{b}{3},\frac{c}{3} ) $

C) $ ( \frac{3}{a},\frac{3}{b},\frac{3}{c} ) $

D) $ ( \frac{1}{3a},\frac{1}{3b},\frac{1}{3c} ) $

Show Answer

Answer:

Correct Answer: D

Solution:

Centroid is $ ( \frac{\frac{1}{a}+0+0}{3},\frac{0+\frac{1}{b}+0}{3},\frac{0+0+\frac{1}{c}}{3} ) $ i.e., $ ,( \frac{1}{3a},\frac{1}{3b},\frac{1}{3c} ) $ .



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