Three Dimensional Geometry Question 41
Question: The plane $ ax+by+cz=1 $ meets the co-ordinate axes in A, B and C. The centroid of the triangle is
[CET 1992]
Options:
A) $ (3a,3b,3c) $
B) $ ( \frac{a}{3},\frac{b}{3},\frac{c}{3} ) $
C) $ ( \frac{3}{a},\frac{3}{b},\frac{3}{c} ) $
D) $ ( \frac{1}{3a},\frac{1}{3b},\frac{1}{3c} ) $
Show Answer
Answer:
Correct Answer: D
Solution:
Centroid is $ ( \frac{\frac{1}{a}+0+0}{3},\frac{0+\frac{1}{b}+0}{3},\frac{0+0+\frac{1}{c}}{3} ) $ i.e., $ ,( \frac{1}{3a},\frac{1}{3b},\frac{1}{3c} ) $ .