Three-Dimensional-Geometry Question 428
Question: If $ A(1,,2,,3),,B(-1,-1,-1) $ be the points, then the distance AB is
[MP PET 2001; Pb. CET 2001]
Options:
A) $ \sqrt{5} $
B) $ \sqrt{21} $
C) $ \sqrt{29} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ AB=\sqrt{{{(-1-1)}^{2}}+{{(-1-2)}^{2}}+{{(-1-3)}^{2}}} $ $ AB=\sqrt{4+9+16}=\sqrt{29} $ .
BETA
