Three Dimensional Geometry Question 53
Question: The equation of a plane which cuts equal intercepts of unit length on the axes, is
[MP PET 1996]
Options:
A) $ x+y+z=0 $
B) $ x+y+z=1 $
C) $ x+y-z=1 $
D) $ \frac{x}{a}+\frac{y}{a}+\frac{z}{a}=1 $
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Answer:
Correct Answer: B
Solution:
Equation of required plane is, $ \frac{x}{1}+\frac{y}{1}+\frac{z}{1}=1 $
$ \Rightarrow ,x+y+z=1 $ .