Three Dimensional Geometry Question 53

Question: The equation of a plane which cuts equal intercepts of unit length on the axes, is

[MP PET 1996]

Options:

A) $ x+y+z=0 $

B) $ x+y+z=1 $

C) $ x+y-z=1 $

D) $ \frac{x}{a}+\frac{y}{a}+\frac{z}{a}=1 $

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Answer:

Correct Answer: B

Solution:

Equation of required plane is, $ \frac{x}{1}+\frac{y}{1}+\frac{z}{1}=1 $
$ \Rightarrow ,x+y+z=1 $ .