Three Dimensional Geometry Question 64
Question: Which of the following set of points are non- collinear
[MP PET 1990]
Options:
A) (1, -1, 1), (-1, 1, 1), (0, 0, 1)
B) (1, 2, 3), (3, 2, 1), (2, 2, 2)
C) (-2,4, -3), (4, -3, -2), (-3, -2, 4)
D) (2, 0, -1), (3, 2, -2), (5, 6, -4)
Show Answer
Answer:
Correct Answer: C
Solution:
Check option, $ \frac{4-(-2)}{-3-4}\ne \frac{-3-4}{-2-(-3)} $ Therefore, this set of points is non-collinear.
BETA
