Three Dimensional Geometry Question 78
Question: The equation of the plane passing through the origin and perpendicular to the line $ x=2y=3z $ is
Options:
A) $ 6x+3y+2z=0 $
B) $ x+2y+3z=0 $
C) $ 3x+2y+z=0 $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Obviously the line is $ \frac{x}{6}=\frac{y}{3}=\frac{z}{2}. $ So required plane is $ 6,(x-0)+3,(y-0)+2,(z-0)=0 $ .
BETA
