Triangles And Properties Of Triangle Question 19
Question: The length of the shadow of a pole inclined at $ 10{}^\circ $ to the vertical towards the sun is 2.05 meters, when the elevation of the sun is $ 38{}^\circ . $ The length of the pole is
Options:
A) $ \frac{2.05\sin 38{}^\circ }{\sin 42{}^\circ } $
B) $ \frac{2.05\sin 42{}^\circ }{\sin 38{}^\circ } $
C) $ \frac{2.05\cos 38{}^\circ }{\cos 42{}^\circ } $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ \frac{\sin 38{}^\circ }{l}=\frac{\sin (SPO)}{2.05} $ $ =\frac{\sin (180{}^\circ -38{}^\circ -90{}^\circ -10{}^\circ )}{2.05} $
$ \Rightarrow l=\frac{2.05\sin 38{}^\circ }{\sin 42{}^\circ } $
BETA
