Triangles And Properties Of Triangle Question 6
Question: A man whose eye level is 1.5 meters above the ground observe the angle of elevation of the tower to be $ 60{}^\circ $ . If the distance of the man from the tower be 10 meters, the height of the tower is
Options:
A) $ (1.5+10\sqrt{3})m $
B) $ 10\sqrt{3}m $
C) $ ( 1.5+\frac{10}{\sqrt{3}} )m $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ H=(10tan60{}^\circ +1.5) $ $ =(10\sqrt{3}+1.5)m $
BETA
