SATHEE: Triangles-And-Properties-Of-Triangle Question 67

Triangles-And-Properties-Of-Triangle Question 67

Question: In a $ \Delta ABC $ , $ \frac{\cos A}{a}=\frac{\cos B}{b}=\frac{\cos C}{c} $ and the side $ a=2, $ then find area of the triangle.

Solution:

Answer: 1.73

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Triangles-And-Properties-Of-Triangle Question 67

Question: In a $ \Delta ABC $ , $ \frac{\cos A}{a}=\frac{\cos B}{b}=\frac{\cos C}{c} $ and the side $ a=2, $ then find area of the triangle.

Solution:

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