Trigonometric Equations Question 1
Question: In $ \Delta ABC,\ ,2R^{2}\sin A\sin B\sin C= $
Options:
A) $ s^{2} $
B) $ ab+bc+ca $
C) $ \Delta $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- $ \frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}=\frac{1}{2R} $
$ \Rightarrow \sin A=\frac{a}{2R} $ etc. Therefore $ 2R^{2}\sin A\sin B\sin C= $ $ 2R^{2}\frac{a}{2R},.,\frac{b}{2R}.\frac{c}{2R} $ $ =\frac{abc}{4R}=\Delta $ .
BETA
