Trigonometric Equations Question 104
Question: If the perpendicular AD divides the base of the triangle ABC such that BD, CD and AD are in the ratio 2, 3 and 6, then angle A is equal to
[MP PET 1993]
Options:
A) $ \frac{\pi }{2} $
B) $ \frac{\pi }{3} $
C) $ \frac{\pi }{4} $
D) $ \frac{\pi }{6} $
Show Answer
Answer:
Correct Answer: C
Solution:
- Obviously, $ \tan A=\frac{\frac{2}{6}+\frac{3}{6}}{1-\frac{2}{6}.\frac{3}{6}}=1 $
Þ $ A=\frac{\pi }{4} $
BETA
