SATHEE: Trigonometric Equations Question 108

Trigonometric Equations Question 108

Question: The inradius of the triangle whose sides are 3, 5, 6, is

[EAMCET 1982]

Options:

A) $ \sqrt{8/7} $

B) $ \sqrt{8} $

C) $ \sqrt{7} $

D) $ \sqrt{7/8} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ r=\frac{\Delta }{s}=\sqrt{\frac{8}{7}} $ .

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Trigonometric Equations Question 108

Question: The inradius of the triangle whose sides are 3, 5, 6, is

Options:

Answer:

Solution:

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