Trigonometric Equations Question 123
Question: The circum-radius of the triangle whose sides are 13, 12 and 5 is
[Karnataka CET 2005]
Options:
A) 15
B) 13/2
C) 15/2
D) 6
Show Answer
Answer:
Correct Answer: B
Solution:
- $ R=\frac{abc}{4\Delta } $ , where $ \Delta =\sqrt{s(s-a)(s-b)(s-c)} $ $ a=13,b=12,c=5,s=\frac{30}{2}=15 $ $ \Delta =\sqrt{15(2)(3)10}=3\times 2\times 5=30 $
$ \therefore R=\frac{13\times 12\times 5}{4\times 30}=\frac{13}{2} $ .
BETA
