Trigonometric Equations Question 125
Question: In an equilateral triangle of side $ 2\sqrt{3} $ cm, the circum-radius is
[EAMCET 1978]
Options:
A) 1 cm
B) $ \sqrt{3} $ cm
C) 2 cm
D) $ 2\sqrt{3} $ cm
Show Answer
Answer:
Correct Answer: C
Solution:
- $ a=b=c=2\sqrt{3} $ $ \Delta =( \frac{\sqrt{3}a^{2}}{4} )=3\sqrt{3}sq.,cm,,\therefore ,R=\frac{abc}{4\Delta }=2cm $ .
BETA
