Trigonometric Equations Question 126
Question: A man from the top of a 100 meters high tower sees a car moving towards the tower at an angle of depression of 30 °. After some time, the angle of depression becomes $ 60^{o} $ . The distance (in meters) travelled by the car during the time is
[IIT Screening 2001]
Options:
A) $ 100\sqrt{3} $
B) $ \frac{200\sqrt{3}}{3} $
C) $ \frac{100\sqrt{3}}{3} $
D) $ 200\sqrt{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
- $ x=QR-QS=100\cot 30^{o}-100\cot 60^{o} $ $ =100\sqrt{3}-\frac{100}{\sqrt{3}}=\frac{200}{\sqrt{3}}=\frac{200\sqrt{3}}{3} $ .
BETA
