Trigonometric Equations Question 145
Question: From the top of a light house 60 meters high with its base at the sea level, the angle of depression of a boat is 15o. The distance of the boat from the foot of light house is
[MNR 1988; IIT 1983; MP PET 1994, 2001; UPSEAT 2000]
Options:
A) $ ( \frac{\sqrt{3}-1}{\sqrt{3}+1} ),60m $
B) $ ( \frac{\sqrt{3}+1}{\sqrt{3}-1} ),60m $
C) $ ( \frac{\sqrt{3}+1}{\sqrt{3}-1} ),m $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- Required distance = $ 60\cot 15^{o}=60( \frac{\sqrt{3}+1}{\sqrt{3}-1} ) $ .
BETA
