Trigonometric Equations Question 156
Question: At a distance 2h from the foot of a tower of height h, the tower and a pole at the top of the tower subtend equal angles. Height of the pole should be
Options:
A) $ \frac{5h}{3} $
B) $ \frac{4h}{3} $
C) $ \frac{7h}{5} $
D) $ \frac{3h}{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \tan \alpha =\frac{1}{2} $ and $ BC=akm $ $ \tan 2\alpha =\frac{2\tan \alpha }{1-{{\tan }^{2}}\alpha }\Rightarrow \frac{p+h}{2h}=\frac{1}{1-\frac{1}{4}} $
$ \Rightarrow $ $ \frac{p+h}{2h}=\frac{4}{3}\Rightarrow p=\frac{5h}{3} $ .
BETA
