Trigonometric Equations Question 16
Question: The angle of elevation of a cliff at a point A on the ground and a point B, 100 m vertically at A are a and b respectively. The height of the cliff is
[EAMCET 1986]
Options:
A) $ \frac{100\cot ,\alpha }{\cot \alpha -\cot \beta } $
B) $ \frac{100\cot \beta }{\cot ,\alpha -\cot ,\beta } $
C) $ \frac{100\cot \beta }{\cot \beta -\cot \alpha } $
D) $ \frac{100\cot \beta }{\cot \beta +\cot \alpha } $
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Answer:
Correct Answer: C
Solution:
- If $ OP=h $ , then $ CP=h-100 $ Now equate the values of $ OA $ and $ BC $ . $ h\cot \alpha =(h-100),\cot \beta $
$ \therefore $ $ h=\frac{100\cot \beta }{\cot \beta -\cot \alpha } $
BETA
