Trigonometric Equations Question 164
Question: Some portion of a 20 meters long tree is broken by the wind and the top struck the ground at an angle of $ 30^{o} $ . The height of the point where the tree is broken is
[MNR 1974]
Options:
A) 10 m
B) $ (2\sqrt{3}-3),20m $
C) $ \frac{20}{3}m $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- $ H=20=l+h,,l=\frac{d}{\cos 30^{o}},,h=d\tan 30^{o} $
$ \therefore $ $ d=\frac{20}{(\sec 30^{o}+\tan 30^{o})}=\frac{20}{\sqrt{3}} $ and hence $ h=d\tan 30^{o}=\frac{20}{3}m $ .
BETA
