Trigonometric Equations Question 185

Question: If in a triangle $ ABC, $ $ (s-a)(s-b)=s(s-c) $ , then angle C is equal to

[MP PET 1986]

Options:

A) $ 90^{o} $

B) $ 45^{o} $

C) $ 30^{o} $

D) $ 60^{o} $

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Answer:

Correct Answer: A

Solution:

  • $ \tan \frac{C}{2}=\sqrt{\frac{(s-a)(s-b)}{s(s-c)}}=1 $ $ =\tan ( \frac{\pi }{4} ) $ , from given data. Hence $ C=90^{o} $ .