Trigonometric Equations Question 185
Question: If in a triangle $ ABC, $ $ (s-a)(s-b)=s(s-c) $ , then angle C is equal to
[MP PET 1986]
Options:
A) $ 90^{o} $
B) $ 45^{o} $
C) $ 30^{o} $
D) $ 60^{o} $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \tan \frac{C}{2}=\sqrt{\frac{(s-a)(s-b)}{s(s-c)}}=1 $ $ =\tan ( \frac{\pi }{4} ) $ , from given data. Hence $ C=90^{o} $ .