Trigonometric Equations Question 186

Question: In a $ \Delta ABC $ , if $ 2s=a+b+c $ and $ (s-b)(s-c)= $ $ x{{\sin }^{2}}\frac{A}{2}, $ then x =

[MP PET 1992]

Options:

A) bc

B) ca

C) ab

D) abc

Show Answer

Answer:

Correct Answer: A

Solution:

  • $ \sin \frac{A}{2}=\sqrt{\frac{(s-b)(s-c)}{bc}} $
    $ \Rightarrow bc{{\sin }^{2}}\frac{A}{2}=(s-b)(s-c) $ Hence $ x=bc $ .