Trigonometric Equations Question 189
Question: In $ \Delta ABC,\frac{\sin B}{\sin (A+B)}= $
[MP PET 1989]
Options:
A) $ \frac{b}{a+b} $
B) $ \frac{b}{c} $
C) $ \frac{c}{b} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- $ \frac{\sin B}{\sin (A+B)}=\frac{\sin B}{\sin C}=\frac{b}{c} $ .
BETA
