Trigonometric Equations Question 196
Question: In a triangle $ ABC $ , if $ a=2,B=60^{o} $ and $ C=75^{o} $ , then b =
[Karnataka CET 1992]
Options:
A) $ \sqrt{3} $
B) $ \sqrt{6} $
C) $ \sqrt{9} $
D) $ 1+\sqrt{2} $
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Answer:
Correct Answer: B
Solution:
- $ B=60^{o} $ , $ C=75^{o} $
Þ $ A=180^{o}-60^{o}-75^{o}=45^{o} $ Now $ \frac{b}{\sin B}=\frac{a}{\sin A} $ Þ $ \frac{b}{\sin 60^{o}}=\frac{2}{\sin 45^{o}}\Rightarrow b=\sqrt{6} $ .
BETA
