Trigonometric Equations Question 208
Question: In triangle ABC, $ A=30^{o},b=8,a=6 $ , then $ B={{\sin }^{-1}}x $ , where x =
[Karnataka CET 1990]
Options:
A) $ \frac{1}{2} $
B) $ \frac{1}{3} $
C) $ \frac{2}{3} $
D) 1
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Answer:
Correct Answer: C
Solution:
- $ \frac{\sin B}{b}=\frac{\sin A}{a} $
Þ $ \sin B=\frac{b\sin A}{a}=\frac{8\sin 30^{o}}{6}=\frac{2}{3} $ .
BETA
