Trigonometric Equations Question 219
Question: If $ \tan \frac{B-C}{2}=x\cot \frac{A}{2}, $ then $ x= $
[MP PET 1992, 2002]
Options:
A) $ \frac{c-a}{c+a} $
B) $ \frac{a-b}{a+b} $
C) $ \frac{b-c}{b+c} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- $ \tan \frac{B-C}{2}=x\cot \frac{A}{2}\Rightarrow x=\frac{b-c}{b+c} $ .
BETA
