Trigonometric Equations Question 226
Question: If the sides of a triangle are in the ratio $ 2:\sqrt{6}:(\sqrt{3}+1) $ , then the largest angle of the triangle will be
[MP PET 1990]
Options:
A) $ 60^{o} $
B) $ 75^{o} $
C) $ 90^{o} $
D) $ 120^{o} $
Show Answer
Answer:
Correct Answer: B
Solution:
- $ \cos \theta =\frac{4+6-{{(\sqrt{3}+1)}^{2}}}{2.2.\sqrt{6}}\Rightarrow \theta =75^{o} $ .
BETA
