Trigonometric Equations Question 24
Question: We are given b, c and $ \sin B $ such that B is acute and $ b<c\sin B $ . Then
[Karnataka CET 1993]
Options:
A) No triangle is possible
B) One triangle is possible
C) Two triangles are possible
D) A right angled triangle is possible
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \frac{\sin B}{b}=\frac{\sin C}{c} $
Þ $ \sin C=\frac{c}{b}\sin B>1 $ $ (\because b<c\sin B) $ ,which is impossible. Hence no triangle is possible.
BETA
