Trigonometric Equations Question 255
Question: If angles of a triangle are in the ratio of 2 : 3: 7, then the sides are in the ratio of
[MP PET 1996]
Options:
A) $ \sqrt{2}:2:(\sqrt{3}+1) $
B) $ 2:\sqrt{2}:(\sqrt{3}+1) $
C) $ \sqrt{2}:(\sqrt{3}+1):2 $
D) $ 2:(\sqrt{3}+1):\sqrt{2} $
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Answer:
Correct Answer: A
Solution:
- Obviously, the angles are $ 30^{o},45^{o},105^{o} $ .
$ \therefore $ $ a:b:c=\sin 30^{o}:\sin 45^{o}:\sin 105^{o} $ $ =\frac{1}{2}:\frac{1}{\sqrt{2}}:\frac{\sqrt{3}+1}{2\sqrt{2}}=\sqrt{2}:2:(\sqrt{3}+1) $ .
BETA
