Trigonometric Equations Question 267
Question: The number of triangles ABC that can be formed with $ a=3,b=8 $ and $ \sin A=\frac{5}{13} $ is
[Roorkee Qualifying 1998]
Options:
A) 0
B) 1
C) 2
D) 3
Show Answer
Answer:
Correct Answer: A
Solution:
- Applying sine rule, $ \frac{\sin B}{b}=\frac{\sin A}{a} $ or $ \frac{\sin B}{8}=\frac{5/13}{3} $ or $ \sin B=\frac{40}{39}>1 $ , which is not possible. Hence no triangle can be formed by the given conditions.
BETA
